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標題:

f3 factorization!!!help!!!

發問:

factorize 3(x+7)^2+(x+7)(x-6)-14(x-6)^2 吾該曬...

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最佳解答:

Let x+7=y, x-6=z 3(x+7)^2+(x+7)(x-6)-14(x-6)^2 =3y^2+yz-14z^2 =(3y+7z)(y-2z) =(3x+21+7x-42)(x+7-2x+12) =(10x-21)(19-x)

其他解答:

Let x+7=y, x-6=z 3(x+7)^2+(x+7)(x-6)-14(x-6)^2 =3y^2+yz-14z^2 =(3y+7z)(y-2z) =(3x+21+7x-42)(x+7-2x+12) =(10x-21)(19-x) ^_^|||||設a=(x+7) b=(x-6) 3(x+7)^2+(x+7)(x-6)-14(x-6)^2 =3a^2+ab-14b^2 =(3a+7b)(a-2b) =[3(x+7)+7(x-6)][(x+7)-2(x-6)] =(3x+21+7x-42)(x+7-2x+12) =(10x-21)(-x+19)
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