close
標題:
【F.4 A.Math】Basic Rule of Inequalities
發問:
Prove that if a ＞b ＞ 0 , then a^2 ＞ b^2 (假設ａ大過ｂ大過０，推證ａ的二次方 大過ｂ的二次方)
As a, b > 0, we have a + b > 0 As a > b, we have a - b > 0 Thus a^2 - b^2 = (a + b)(a - b) > 0 [The product of two positive numbers is positive] Hence a^2 > b^2
其他解答:
Let a be 4and b be 2, a^2=4^2=16 b^2=2^2=4 Therefore,a^2>b^2 if a>b>c.
【F.4 A.Math】Basic Rule of Inequalities
發問:
Prove that if a ＞b ＞ 0 , then a^2 ＞ b^2 (假設ａ大過ｂ大過０，推證ａ的二次方 大過ｂ的二次方)
此文章來自奇摩知識+如有不便請留言告知
最佳解答:As a, b > 0, we have a + b > 0 As a > b, we have a - b > 0 Thus a^2 - b^2 = (a + b)(a - b) > 0 [The product of two positive numbers is positive] Hence a^2 > b^2
其他解答:
Let a be 4and b be 2, a^2=4^2=16 b^2=2^2=4 Therefore,a^2>b^2 if a>b>c.
文章標籤
全站熱搜
留言列表
