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有兩條英文數學題唔識(圓周) (要有步驟)
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最佳解答:
Q1. Let radius of quadrant = r Perimeter of quadrant = r + r + 2pr(90/360) = 2r + pr/2 (p = pi) so 2r + pr/2 = 32 4r + pr = 64 r(4 + p) = 64 r = 64/(4 + p). so area enclosed = pr^2/4 = (p/4)[64/(4 + p)]^2 = 1024p/(4 + p)^2. Q2. In 1 sec. length of water running out = 0.8m = 80 cm. so volume of water running out = p(2.6/2)^2(80) = p(1.3)^2(80) = 135.2p cm^3.
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有兩條英文數學題唔識(圓周) (要有步驟)
發問:
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(1) a wire 32 cm long, is bent into the shape of a qusdrant. Find the area enclosed by wire. (2) A water pipe of internal diameter 2.6cm delivers water at a rate of 0.8m/s.How much water comes outper second.最佳解答:
Q1. Let radius of quadrant = r Perimeter of quadrant = r + r + 2pr(90/360) = 2r + pr/2 (p = pi) so 2r + pr/2 = 32 4r + pr = 64 r(4 + p) = 64 r = 64/(4 + p). so area enclosed = pr^2/4 = (p/4)[64/(4 + p)]^2 = 1024p/(4 + p)^2. Q2. In 1 sec. length of water running out = 0.8m = 80 cm. so volume of water running out = p(2.6/2)^2(80) = p(1.3)^2(80) = 135.2p cm^3.
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