標題:
Graphs of Functions (20 marks) --- Urgent!!!!!!!!!!!!!!!!!!!
1. The graph of y=a(x-h)^2+k passes through A (-8, -36) and cuts the x-axis at B (-10,0) and C (-2, 0).(a) Find the values of a, h, k.(b) Find the minimum value of y.(c) Find the y-intercept of the graph.Please answer the above questions and show the steps clearly, thanks!!!If you are not sure how to answer... 顯示更多 1. The graph of y=a(x-h)^2+k passes through A (-8, -36) and cuts the x-axis at B (-10,0) and C (-2, 0). (a) Find the values of a, h, k. (b) Find the minimum value of y. (c) Find the y-intercept of the graph. Please answer the above questions and show the steps clearly, thanks!!! If you are not sure how to answer the above three questions, please do not answer, thanks!!!
最佳解答:
1. The graph of y=a(x-h)^2+k passes through A (-8, -36) and cuts the x-axis at B (-10,0) and C (-2, 0). (a) Find the values of a, h, k. -10, -2 are roots y = a(x + 10)(x + 2) -36 = a(-8 + 10)(-8 + 2) a = 3 y = 3(x + 10)(x + 2) = 3(x^2 + 12x + 20) = 3(x^2 + 12x + 36 - 16) = 3 [(x + 6)^2 - 16] = 3 [ ( x - (-6) )^2 - 16 ] a = 3, h = -6, k = -16 (b) Find the minimum value of y. minimum value of y = (3)(-16) = -48 (c) Find the y-intercept of the graph. when x = 0, y = 3(0 + 10)(0 + 2) = 60 y-intercept = 60
其他解答:
Graphs of Functions (20 marks) --- Urgent!!!!!!!!!!!!!!!!!!!
此文章來自奇摩知識+如有不便請留言告知
發問:1. The graph of y=a(x-h)^2+k passes through A (-8, -36) and cuts the x-axis at B (-10,0) and C (-2, 0).(a) Find the values of a, h, k.(b) Find the minimum value of y.(c) Find the y-intercept of the graph.Please answer the above questions and show the steps clearly, thanks!!!If you are not sure how to answer... 顯示更多 1. The graph of y=a(x-h)^2+k passes through A (-8, -36) and cuts the x-axis at B (-10,0) and C (-2, 0). (a) Find the values of a, h, k. (b) Find the minimum value of y. (c) Find the y-intercept of the graph. Please answer the above questions and show the steps clearly, thanks!!! If you are not sure how to answer the above three questions, please do not answer, thanks!!!
最佳解答:
1. The graph of y=a(x-h)^2+k passes through A (-8, -36) and cuts the x-axis at B (-10,0) and C (-2, 0). (a) Find the values of a, h, k. -10, -2 are roots y = a(x + 10)(x + 2) -36 = a(-8 + 10)(-8 + 2) a = 3 y = 3(x + 10)(x + 2) = 3(x^2 + 12x + 20) = 3(x^2 + 12x + 36 - 16) = 3 [(x + 6)^2 - 16] = 3 [ ( x - (-6) )^2 - 16 ] a = 3, h = -6, k = -16 (b) Find the minimum value of y. minimum value of y = (3)(-16) = -48 (c) Find the y-intercept of the graph. when x = 0, y = 3(0 + 10)(0 + 2) = 60 y-intercept = 60
其他解答:
文章標籤
全站熱搜
留言列表
