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Physic~ about gravity
A man throws a rock vertically upward ( from ground level) and it reaches a maximum height of 37.5 ft and hits the ground 5 seconds after it leaves his hand. Find the gravity~
最佳解答:
Use equation of motion: s = vt - (1/2)gt^2 for the upward journey with s = 37.5 ft., v = 0 m/s, t = 5/2 s = 2.5 s, a = -g (the acceleration due to gravity) Hence, 37.5 = -(1/2)(-g).(2.5^2) g = 2 x 37.5/2.5^2 ft/s^2 = 12 ft/s^2 p.s. The correct value of g on earth should be 32 ft/s^2. Please check if the given data are correct.
其他解答:
Physic~ about gravity
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發問:A man throws a rock vertically upward ( from ground level) and it reaches a maximum height of 37.5 ft and hits the ground 5 seconds after it leaves his hand. Find the gravity~
最佳解答:
Use equation of motion: s = vt - (1/2)gt^2 for the upward journey with s = 37.5 ft., v = 0 m/s, t = 5/2 s = 2.5 s, a = -g (the acceleration due to gravity) Hence, 37.5 = -(1/2)(-g).(2.5^2) g = 2 x 37.5/2.5^2 ft/s^2 = 12 ft/s^2 p.s. The correct value of g on earth should be 32 ft/s^2. Please check if the given data are correct.
其他解答:
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