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標題:

問2題數學題

發問:

1.There are 2 consecutive positive odd number.The sum of the smaller number and one-third of the lager number is less than or equal to 10.Find the greatest of the smaller number. 2.x is greater than y by5,and the sum of x and y is less than 49.Find the largerest value of x if x is integer.

最佳解答:

1. let the two numbers be 2x+1, 2x+3 (2x+3)/3+2x+1<=10 2x+3+6x+3<=30 8x<=24 x<=3 Thus, the greatest of the smaller number = 2*3+1 = 7 2. x+5=y, x+y<49 2x+5<49 2x<44 x<22 Thus, the largest value of x is 21 2007-05-03 16:21:19 補充： 睇錯...x is greater than y by5, 即y 5=x2. 2x-5 2007-05-03 17:59:33 補充： y加5=xthe largest value of x is 26

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其他解答:

Q1 Answer: Let x be the smaller number and x+2 be the larger number x + 1/3 *(x+2) <= 10 (4/3)*x + 2/3 <= 10 (4/3)*x <= 28/3 x<= 7 then the largest value for x is 7 Q2 Answer: Solve the below two equations ----- x-y = 5 ..............................(1) and x+y <49 ........................(2) From (1), y = x-5 sub into (2), x+(x-5) < 49 2x-5<49 2x<54 x<27 then the largest value for x is 26 as 26<27 and is an integer