標題:
Inequality
發問:
最佳解答:
With the roots being real, we have: (1 - k)2 - 4 x 625 >= 0 (k - 1)2 >= 4 x 625 k - 1 >= 50 or k - 1 <= -50 k >= 51 or k <= -49 Then combining with -(1 - k) < 0 (since the roots are negative, their sum should be negative too) 1 - k > 0 k < 1 So combined together, we have k <= -49
其他解答:
Inequality
發問:
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Consider a quadratic equation x^2 + (1 - k)x + 625 = 0. If the roots of the quadratic equation are negative, find the range of possible values of k. Ans: k <= 49最佳解答:
With the roots being real, we have: (1 - k)2 - 4 x 625 >= 0 (k - 1)2 >= 4 x 625 k - 1 >= 50 or k - 1 <= -50 k >= 51 or k <= -49 Then combining with -(1 - k) < 0 (since the roots are negative, their sum should be negative too) 1 - k > 0 k < 1 So combined together, we have k <= -49
其他解答:
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