標題:
數學應用題１０點
發問:
把45顆巧克力分成兩份，其中小份的5倍比大份的三倍多1顆，求小份有巧克力多少顆。請例式！！！最好用ENG
最佳解答:
Let the smaller portion be x. Therefore, 5 times of x = 5x. Larger portion = (45-x), 3 times of larger portion = 3(45-x). Therefore, the equation is: 5x - 3(45-x) = 1 5x - 135 + 3x = 1 8x = 136 x= 17 = quantity of smaller portion.
其他解答:
let x be the smaller one and y be the more one , x + y = 45 --------------------(1) 5x - 3y = 1 -------------------(2) (1) * 3 , 3x + 3y = 135 ----------------(3) (2) + (3) 5x - 3y + 3x + 3y = 1 + 135 8x = 136 x = 17 sub x = 17 into (1) , 17 + y = 45 y = 28 Therefore , the smaller one have 17 chocolates .|||||Let x be the number of the chocolate in the larger group, and y be the number of chocolate in the fewer group. from the above, we can have : x+y=45 ---(1) 5y-3x=1 ---(2) from (1) : x = 45-y ---(3) sub. (3) into (2) 5y-3(45-y) = 1 5y-135+3y = 1 8y = 136 y = 17 when y = 17 , x = 28 so, chocolate is divided into two groups, 28 pieces and 17 pieces.
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