標題:
MATH...好趕架
發問:
我想問 1b) 果題點計... 但唔要: 6^3+2^3 =(6*6*6)+(2*2*2) =(36*6)+(4*2) =216+8 = 224 1a)Expand (x+y)(x^2-xy+y^2) 1b)Hence,find the value of 6^3+2^3 without using a calculator. 更新: 2. 2x-6y/3y-x 3. -x^2+1/x+1 4. 2p-10r/r^2÷3p-15r/6pr
最佳解答:
你只要做完 1a 你便知道 原來... (x+y)(x^2-xy+y^2) = x^3 + y^3 所以 1b 會用返 1a 條式 6^3 + 2^3 = (6+2)(6^2-6*2+2^2) <- 將 6 和 2 分別代入 x 和 y = 8*(36-12+4) = 8*(28) = 224 記緊 若題目有分題, 且有 hence 或 thus 字樣 便是代表呢個分題同 part a 有關 用返 1a 條式就可以了
1a) (x+y)(x2-xy+y2) =(x)(x2-xy+y2)+(y)(x2-xy+y2) =(x3-x2y+xy2)+(x2y-xy2+y3) =x3-x2y+xy2+x2y-xy2+y3 1b) (63+23) =(6+2)[62-(6)(2)+22] =(8)(36-12+4) =(8)(28) =224 2) 2x-6y/3y-x = 2x-6y/-(x-3y) =2(x-3y)/-(x-3y) =2/-1 =- 2/1 2) -x2+1/x+1 =- (x)(x+1)/x+1 = -x 3) 2p-10r/r2 ÷ 30-15r/6pr = 2p-10r/r2 ÷ 6pr/3p-15r = 2(p-5r)/r2 ÷ 6pr/3(p-5r) = (2)(6p)/(r)(3) = (2)(2p)/r = 4p/r 2007-11-06 20:57:54 補充： Question 2= -2/1should be:= -2
MATH...好趕架
發問:
我想問 1b) 果題點計... 但唔要: 6^3+2^3 =(6*6*6)+(2*2*2) =(36*6)+(4*2) =216+8 = 224 1a)Expand (x+y)(x^2-xy+y^2) 1b)Hence,find the value of 6^3+2^3 without using a calculator. 更新: 2. 2x-6y/3y-x 3. -x^2+1/x+1 4. 2p-10r/r^2÷3p-15r/6pr
最佳解答:
你只要做完 1a 你便知道 原來... (x+y)(x^2-xy+y^2) = x^3 + y^3 所以 1b 會用返 1a 條式 6^3 + 2^3 = (6+2)(6^2-6*2+2^2) <- 將 6 和 2 分別代入 x 和 y = 8*(36-12+4) = 8*(28) = 224 記緊 若題目有分題, 且有 hence 或 thus 字樣 便是代表呢個分題同 part a 有關 用返 1a 條式就可以了
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其他解答:1a) (x+y)(x2-xy+y2) =(x)(x2-xy+y2)+(y)(x2-xy+y2) =(x3-x2y+xy2)+(x2y-xy2+y3) =x3-x2y+xy2+x2y-xy2+y3 1b) (63+23) =(6+2)[62-(6)(2)+22] =(8)(36-12+4) =(8)(28) =224 2) 2x-6y/3y-x = 2x-6y/-(x-3y) =2(x-3y)/-(x-3y) =2/-1 =- 2/1 2) -x2+1/x+1 =- (x)(x+1)/x+1 = -x 3) 2p-10r/r2 ÷ 30-15r/6pr = 2p-10r/r2 ÷ 6pr/3p-15r = 2(p-5r)/r2 ÷ 6pr/3(p-5r) = (2)(6p)/(r)(3) = (2)(2p)/r = 4p/r 2007-11-06 20:57:54 補充： Question 2= -2/1should be:= -2
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