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三角恆等式問題!

發問:

求詳細步驟! 17. cos43°=sin(75°-Θ) 答案:28° 18. sin32°=cos(66°-Θ/2) 答案:16° 19. tan(Θ+15°)=1/tan(Θ+60°) 答案:7.5° 20. tan(Θ+45°)=1/tanΘ/4 答案:36°

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17)cos43° = sin(75°-Θ)sin(90 - 43) = sin(75 - Θ)90 - 43 = 75 - ΘΘ = 28° 18)sin32° = cos(66° - Θ/2)cos(90 - 32) = cos(66° - Θ/2)90 - 32 = 66 - Θ/2Θ/2 = 8Θ = 16° 19)tan(Θ+15°) = 1 / tan(Θ+60°)tan(Θ+15) = tan(90 - (Θ+60))Θ+15 = 90 - (Θ+60)2Θ = 15Θ = 7.5° 20)tan(Θ+45°) = 1 / tan(Θ/4)tan(Θ+45°) = = tan(90 - Θ/4)Θ+45° = 90 - Θ/44Θ + 180 = 360 - Θ5Θ = 180Θ = 36°

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