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35.When an allkali is added to Zn(NO3)2 solution,a white ppt is formed.This show thatA. the alkali contains OH-B. the allkali contains metallic ionsC. ZnO is insoluble in waterD. the alkali is strong electrolyteWhy the answer is A but NOT C?36. Which of the following hydroxides would react with both acid and... 顯示更多 35.When an allkali is added to Zn(NO3)2 solution,a white ppt is formed.This show that A. the alkali contains OH- B. the allkali contains metallic ions C. ZnO is insoluble in water D. the alkali is strong electrolyte Why the answer is A but NOT C? 36. Which of the following hydroxides would react with both acid and alkali to give a salt and water A Zinc hydroxide B copper(II) hydroxide C iron(II) hydroxide D calcium hydroxide
最佳解答:
35. The precipitate is Zn(OH)2, but not ZnO. Equation : Zn2+(aq) + 2OH-(aq) → Zn(OH)2(s) ===== 36. The answer is A, because Zn(OH)2 is amphoteric (兩性的) which can neutralize both strong acids and strong alkalis. Zn(OH)2(s) + 2H+(aq) → Zn2+(aq) + 2H2O(l) Zn(OH)2(s) + 2OH-(aq) → [Zn(OH4)]2-(aq) The second reaction does not give water as a product. However, hydroxide ions are consumed and a salt, [Zn(OH4)]2-(aq), is formed. The reaction is also classified as “neutralization”.
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alkali發問:
35.When an allkali is added to Zn(NO3)2 solution,a white ppt is formed.This show thatA. the alkali contains OH-B. the allkali contains metallic ionsC. ZnO is insoluble in waterD. the alkali is strong electrolyteWhy the answer is A but NOT C?36. Which of the following hydroxides would react with both acid and... 顯示更多 35.When an allkali is added to Zn(NO3)2 solution,a white ppt is formed.This show that A. the alkali contains OH- B. the allkali contains metallic ions C. ZnO is insoluble in water D. the alkali is strong electrolyte Why the answer is A but NOT C? 36. Which of the following hydroxides would react with both acid and alkali to give a salt and water A Zinc hydroxide B copper(II) hydroxide C iron(II) hydroxide D calcium hydroxide
最佳解答:
35. The precipitate is Zn(OH)2, but not ZnO. Equation : Zn2+(aq) + 2OH-(aq) → Zn(OH)2(s) ===== 36. The answer is A, because Zn(OH)2 is amphoteric (兩性的) which can neutralize both strong acids and strong alkalis. Zn(OH)2(s) + 2H+(aq) → Zn2+(aq) + 2H2O(l) Zn(OH)2(s) + 2OH-(aq) → [Zn(OH4)]2-(aq) The second reaction does not give water as a product. However, hydroxide ions are consumed and a salt, [Zn(OH4)]2-(aq), is formed. The reaction is also classified as “neutralization”.
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