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F.2 ratio 文字題，help~!!!!!
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最佳解答:
John shares 100 marbles with Jack in the ratio 1 : 3. so, John has 25 and Jack has 75 Jack then gives 45 of his marbles to Joseph. so, Jack has 30 and Joseph has 45 the ratio of John's number of marbles to that of Jack to that of Joseph. = 25 : 30 : 45 = 5 : 6 : 9 如有不足/有錯 請發信聯絡 另外，嚴禁抄襲！ 請發問者/投票者慎選答案 還有的是人家答了大家就不要答！ 加我好友^_^ 2012-01-05 20:06:08 補充： well...since someone copied my answers before and finally got the "best answer", i don't know this happen again. 2012-01-06 18:26:21 補充： (a) let Mary has k $2-coins 28*5 : k*2 = 35 : 24 140 : 2k = 35 : 24 70 / k = 70 / 48 k = 48 2012-01-06 18:29:54 補充： (b) let Mary has n $0.5-coins 28*5 : 48*2 : n*0.5 = 35 : 24 : 11 140 : 96 : 0.5n = 140 : 96 : 44 0.5n = 44 n = 88 ratio of the number of $5-coins to $2-coins to $0.5-coins is 28 : 48 : 88 = 7 : 12 : 22
其他解答:
Mary has 28 $5-coins, some $2-coins and some $0.5-coins. If the ratio of the value of $5-coins to that of $2-coins to that of $0.5-coins is 35 : 24 : 11, find (a) the number of $ 2-coins Mary has, let A be the number of $2-coins 2 x A / (5 x 28 + 2 x A) = 24 / (24 + 35) 2A x 59 = 24 x (140 + 2A) 118A = 3360 + 48A 70A = 3360 A = 48 (b) the ratio of the number of $5-coins to $2-coins to $0.5-coins Let B be the number of $0.5-coins 0.5 x B / (5 x 28 + 0.5 x B) = 11 / (11 + 35) 0.5B x 46 = 11 x (140 + 0.5B) 23B = 1540 + 5.5B 17.5B = 1540 B = 88 the ratio of the number of $5-coins to $2-coins to $0.5-coins : 28 : 48 : 88 = 7 : 12 : 22|||||人家答了大家就不要答? 是何道理? 為何你那麼霸道不准人答? 我都係HKCEE A grade , 年年出幾千個...|||||原來係搵佢地最終有既波子既比率... 2012-01-05 20:00:50 補充： 唔該晒你丫~! :D
F.2 ratio 文字題，help~!!!!!
發問:
此文章來自奇摩知識+如有不便請留言告知
John shares 100 marbles with Jack in the ratio 1 : 3. Jack then gives 45 of his marbles to Joseph. Find the ratio of John's number of marbles to that of Jack to that of Joseph. 更新: Mary has 28 $5-coins, some $2-coins and some $0.5-coins. If the ratio of the value of $5-coins to that of $2-coins to that of $0.5-coins is 35 : 24 : 11, find (a) the number of $ 2-coins Mary has, (b) the ratio of the number of $5-coins to $2-coins to $0.5-coins最佳解答:
John shares 100 marbles with Jack in the ratio 1 : 3. so, John has 25 and Jack has 75 Jack then gives 45 of his marbles to Joseph. so, Jack has 30 and Joseph has 45 the ratio of John's number of marbles to that of Jack to that of Joseph. = 25 : 30 : 45 = 5 : 6 : 9 如有不足/有錯 請發信聯絡 另外，嚴禁抄襲！ 請發問者/投票者慎選答案 還有的是人家答了大家就不要答！ 加我好友^_^ 2012-01-05 20:06:08 補充： well...since someone copied my answers before and finally got the "best answer", i don't know this happen again. 2012-01-06 18:26:21 補充： (a) let Mary has k $2-coins 28*5 : k*2 = 35 : 24 140 : 2k = 35 : 24 70 / k = 70 / 48 k = 48 2012-01-06 18:29:54 補充： (b) let Mary has n $0.5-coins 28*5 : 48*2 : n*0.5 = 35 : 24 : 11 140 : 96 : 0.5n = 140 : 96 : 44 0.5n = 44 n = 88 ratio of the number of $5-coins to $2-coins to $0.5-coins is 28 : 48 : 88 = 7 : 12 : 22
其他解答:
Mary has 28 $5-coins, some $2-coins and some $0.5-coins. If the ratio of the value of $5-coins to that of $2-coins to that of $0.5-coins is 35 : 24 : 11, find (a) the number of $ 2-coins Mary has, let A be the number of $2-coins 2 x A / (5 x 28 + 2 x A) = 24 / (24 + 35) 2A x 59 = 24 x (140 + 2A) 118A = 3360 + 48A 70A = 3360 A = 48 (b) the ratio of the number of $5-coins to $2-coins to $0.5-coins Let B be the number of $0.5-coins 0.5 x B / (5 x 28 + 0.5 x B) = 11 / (11 + 35) 0.5B x 46 = 11 x (140 + 0.5B) 23B = 1540 + 5.5B 17.5B = 1540 B = 88 the ratio of the number of $5-coins to $2-coins to $0.5-coins : 28 : 48 : 88 = 7 : 12 : 22|||||人家答了大家就不要答? 是何道理? 為何你那麼霸道不准人答? 我都係HKCEE A grade , 年年出幾千個...|||||原來係搵佢地最終有既波子既比率... 2012-01-05 20:00:50 補充： 唔該晒你丫~! :D
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